Mathematics, 19.02.2020 04:51 aylagwilliamson

Which are true of the function f(x)=49(1/7)^x
select three options.

1) the domain is the set of all real numbers

2) the range is the set of all real numbers

3) the domain is x>0

4) the range is y>0

5) as x increased by 1, each y-value is one seventh of the previous y-value

Answers: 3

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Answers

Answer from: ambercable3

The Option (1),(4) and (5) are correct.

Step-by-step explanation:

The function given to us is : y= f(x) =49(1/7)^x

The following statements are true regarding the above function is

As you can see that the value of y(49)is defined for all values of x , so the Domain is the set of all values of x , which is set of all real numbers.X is defined for all values of y. So the Range of all the values that y can take is also set of all real numbers greater than zero, i.e y>0.As x increased by 1, each y-value is one seventh of the previous y-value

Answer from: yournerdybirdyp43oi3

The correct options are 1, 4 and 5.

Step-by-step explanation:

The general form of an exponential function is

f(x)=ab^x

where, a is initial value and b is growth factor.

Domain of this function is all real numbers. If a>0, then range is all positive numbers.

The given function is

$f(x)=49(\frac{1}{7})^x$

where, a =49 and b=1/7.

It is an exponential function. So, the domain is the set of all real numbers.

Since, a=49 which is a positive value, therefore the range is y>0.

The value of b is 1/7, it means as x increased by 1, each y-value is one seventh of the previous y-value.

Therefore, the correct options are 1, 4 and 5.

Answer from: Quest

Answercounterclockwise rotation about the origin by 180 degrees followed by reflection about the y-axisexplanationthe given figure has vertices $p(1,2),q(2,1),r(3,2),s(3,3)$ recall that for counterclockwise rotation about the origin, $(x,y)\rightarrow (-x,-y)$ when we rotate figure pqrs counterclockwise through an angle of 180° about the origin, the coordinates will become $p1( - 1, - 2),q1( - 2, - 1),r1( - 3, - 2),s1( - 3, - 3)$ next, we reflect in the y-axis by negating the x-coordinates of the resulting figure to obtain, $p'(1, - 2),q'(2, - 1),r'(3, - 2),s'(3, - 3)$ therefore the correct answer is c

Answer from: Quest

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.