A squirrel is 24 feet up in a tree and tosses a nut out of the tree with an initial velocity of 8 feet per second. the nuts height, h, at time t seconds can be represented by the equation h(t)=-16t^2+8t+24. if the squirrel climbs down the tree in 2 seconds, does it reach the ground before the nut?

The nut lands first on gorund

Solution:

The squirrel climbs down the tree in 2 seconds

Given that,

A squirrel is 24 feet up in a tree and tosses a nut out of the tree with an initial velocity of 8 feet per second

The nuts height, h, at time t seconds can be represented by the equation:

time cannot be negative, so ignore t = -1

Thus the nut takes 1.5 seconds to reach ground

From given,

The squirrel climbs down the tree in 2 seconds

Therefore, the nut lands first on gorund

11

step-by-step explanation:

32.50-7.50=25

225/25=11

the circumference of a circle is, 10.676 cm.

step-by-step explanation:

the formula for circumference of a circle is given by:

where

c is the circumference of a circle and

d is the diameter of a circle.

given: diameter(d) = 3.4 cm and use

substitute these values in [1] we get;

cm

therefore, the circumference of a circle is, 10.676 cm