Two students stting in adjacent seats in a lecture room have weights of 569 N and 673 N. Assume that Newton's law of universal gravitation can be applied to these two students and find the gravitational force (in Newtons) that one student exerts on the other when they are separated by 0.628 m.

6.73 x 10^-7 N.

Step-by-step explanation:

F1 = M1 * a

M1 = 569/9.81

= 58 kg

F2 = M2 * a

M2 = 673/9?81

= 68.6 kg

r = 0.628 m

Using force of attraction, F = (GM1M2)/r^2

Where,

G = 6.67408 × 10-11 m3/kg.s

F = (6.67408 × 10-11 * 68.6 * 58)/(0.628)^2

= 6.73 x 10^-7 N.

option: d is the correct answer.

d) none of the above.

step-by-step explanation:

clearly from the figure attached to the question we could see that there is no shape given. hence without any shape given in the figure and after rotation we can't obtained a square pyramid.

since, to obtain a image we need a proper figure of the pre-image so that it can be transformed.

hence, the correct answer is:

d) none of the above.

step-by-step explanation: