Two fish tanks contained of water altogether. 60 degrees % of the water was scooped out from the first fish tank and 0.6L of water was scooped out from the second fish tank. At the end. both fish tanks had the same amount of water. Find the original volume of water in each fish tank at the beginning ?
PLEASE HELP

2.4

Step-by-step explanation:

let a = vol in the 1st tank (in liters)

let b = vol in the 2nd tank

:

"Two fish tanks contained 9L of water altogether."

a + b = 9

:

" 60% of the water was scooped out from the first tank"

a - .6a = .4a amt in the 1st tank now

:

" and 0.6L of the water was scooped out of the 2nd tank."

a - .6 = amt in the 2nd tank

:

" At the end both fish tanks had the same amount of water. "

.4a = b - .6

.4a - b = -.6

use elimination with the first equation

.4a - b = -.6

a + b = 9

addition eliminates b, find a

1.4a + 0 = 8.4

a = 8.4/1.4

a = 6 liters in the 1st tank

then, obviously,

9 - 6 = 3 liters in the 2nd

:

:

Confirm this in the 2nd statement

" 0.6L of the water was scooped out of the 2nd tank. At the end both fish tanks had the same amount of water. "

.4(6) = 3 - .6

2.4 = 2.4

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step-by-step explanation:

see below

step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

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