The sum of three consecutive intergers is 57 find the intergers

We know that "consecutive" means next to each other.

Let's make "x" the first integer, x+1 the second, and x+2 the third. For example, we could make x = 1.

Then we can plug this into our equation:

x + (x+1) + (x+2) = 57.

1 + (1+1) + (1+2) = 57

1 + 2 + 3 = 57.

So as you can tell, this does NOT work.

Let's continue the original equation:

x + (x+1) + (x+2) = 57.

Combine like terms:

x + x + 1 + x + 2 = 57.

3x = 57 - 2 - 1.

3x = 54.

x = 18.

x + 1 = 19

x + 2 = 20.

Add these up for proof: 18 + 19 + 20 = 57

:)

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

77

step-by-step explanation: