The sum of three consecutive intergers is 57 find the intergers

We know that "consecutive" means next to each other.

Let's make "x" the first integer, x+1 the second, and x+2 the third. For example, we could make x = 1.

Then we can plug this into our equation:

x + (x+1) + (x+2) = 57.

1 + (1+1) + (1+2) = 57

1 + 2 + 3 = 57.

So as you can tell, this does NOT work.

Let's continue the original equation:

x + (x+1) + (x+2) = 57.

Combine like terms:

x + x + 1 + x + 2 = 57.

3x = 57 - 2 - 1.

3x = 54.

x = 18.

x + 1 = 19

x + 2 = 20.

Add these up for proof: 18 + 19 + 20 = 57

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step-by-step explanation:

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