A company that manufactures video cameras produces a basic model and a deluxe model. Over the past year, 30% of the cameras sold have been of the basic model. Of those buying the basic model, 44% purchase an extended warranty, whereas 40% of all deluxe purchasers do so. If you learn that a randomly selected purchaser has an extended warranty, how likely is it that he or she has a basic model?

the probability is 0.32 (32%)

Step-by-step explanation:

defining the event W= has extended warranty , then

P(W)= probability of purchasing the basic model * probability of purchasing extended warranty given that has purchased the basic model + probability of purchasing the deluxe model * probability of purchasing extended warranty given that has purchased the deluxe model = 0.3 * 0.44 + 0.7 * 0.40 = 0.412

then using the theorem of Bayes for conditional probability and defining the event B= has the basic model , then

P(B/W)= P(B∩W)/P(W)= 0.3 * 0.44/0.412 =0.32 (32%)

where

P(B∩W)= probability of purchasing the basic model and purchasing the extended warranty

P(B/W) = probability of purchasing the basic model given that has purchased the extended warranty

option 1

data plot with   3 dots over 33, 1 dot over 34, 2 dots over 35, no dot over 36, 1 dot over 37, 2 dots over 38, 4 dots over 39, and 2 dot over 40.

answer: i'm great at algebra

~coco

step-by-step explanation: