Suppose that you want to solve a bunch of independent quadratic equations all at the same time, each solving the equation: ax2+bx+c = 0 You can do this in your code if you allow the coefficients to be arrays instead of scalars. Modify your script from exercise 1 to solve for quadratic equations having: a = [1 1 1]; b = [-5 -7 3]; c = [6 6 -4]; What are the three independent quadratic equations that are represented here? What are the solutions? Does your MATLAB script find the correct solutions?

y = - 6

step-by-step explanation:

given the point (- 2, y) lies on the graph then it is a solution of it's equation.

substitute x = - 2 into the equation for value of y

y = 3(- 2) = 3 × - 2 = - 6

the point on the graph is (- 2, 6)

$27.5

step-by-step explanation:

$110.00 divided by 4

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

they go with it happens or they mite give a chance?

step-by-step explanation: