An urn contains 5 red, 6 blue, and 8 green balls. If a set of 3 balls is randomly selected, what is the probability that each of the balls will be (a) of the same color? (b) of different colors? Repeat under the assumption that whenever a ball is selected, its color is noted

Answers:

without replacement: a) 86/969   b)80/323

with replacement: a)853/6859      b)1440/6859

Step-by-step explanation:

if the balls are not replaced

the equal probable results of experiment

the outcome space :

, and there are 19.18.17 elements in S.

where

R- event that all three balls are red.

G- events that all three balls are green.

B- events that all three balls are blue.

and the number of possibilities from S that are in Red is 5.4.3 there are 6.5.4 events in blue, and 8.7.6 in green

if the balls are placed

the equal probable results of experiment

the outcome space :

and there are 19.19.19 elements in S.

R- event that all three balls are red.

G- events that all three balls are green.

B- events that all three balls are blue.

and the number of possibilities from S are in red is  5.5.5, there are 6.6.6 events in blue  and 8.8.8 in green

thus the result is:

if the balls are not replaced

the equal probable results of experiment

the outcome space :

and there are 19.18.17 elements in S

and if all balls have to be in different colors.

choose one of the 5 red balls, 1 of the 6 green balls and 1 of the 8 green balls. and for every choice of red, a green and a blue ball they can be permuted 3! ways

if the balls are replaces then

24+x=y

step-by-step explanation:

umm im not really sure because i never had to do this

step-by-step explanation: