If h(x) = squareroot 3 + 2f'(x), where f(5) = 3 and f '(5) = 2, find h'(5).

Chain rule of differentiation is used to find the derivative of composite functions

Reason:

Given function:

Correction

f(5) = 3

f'(5) = 2

By chain rule of differentiation, we have;

Therefore;

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h'(5) = ⅔

Step-by-step explanation:

I assume you mean h(x) = √(3 + 2f(x)).

Taking derivative using chain rule:

h'(x) = ½ (3 + 2f(x))^-½ · 2f'(x)

h'(x) = f'(x) / √(3 + 2f(x))

h'(5) = f'(5) / √(3 + 2f(5))

h'(5) = 2 / √(3 + 2 · 3)

h'(5) = ⅔

is only a line? i think so

both graphs increase on their domain

neither graph has a y-intercept

step-by-step explanation:

the following points can be visualized easily from the graph