How do you do this question?

B) y − 3 = -e (x + 1)

Step-by-step explanation:

Use second fundamental theorem of calculus.

y = 3 − ∫₋₁ˣ e^(-t³) dt

dy/dx = -e^(-x³) (1)

At x = -1:

y = 3

dy/dx =  -e

Using point-slope form, the equation of the tangent line is:

y − 3 = -e (x + 1)