Two dice are tossed. Assume that each possible outcome has a probability. Let A be the event that the sum of the faces showing is 6, and let B be the event that the face showing on one die is twice the face showing on the other. Calculate .

Step-by-step explanation:

Total possible outcome is:

= 36 total possible outcome

Event A(sum of the faces showing 6) = (1, 5), (2, 4), (3, 3), (4, 2), (5, 1) = 5

Event B(one die twice the face of another) = (1, 2), (2, 1), (2, 4), (3, 6), (4, 2), (6, 3)  

B' (B-complement) comprises of all the other possible outcome except those listed for B.

Therefore, among all the other possible outcome, those possible together with Event A are {(1, 5), (3, 3), (5, 1)} = 3

1/12 is the probability of events that can occur in Event A and the complement of B.