Determine the dimensions of the constants A and B from the following derivative where y has the dimension of length and t has the dimension of time. (Use the following as necessary: L and T, where L is the unit of length and T is the unit of time.) dy/dt

1. A=L/T^3

2. B=L/T

Step-by-step explanation:

Assume the equation y = At^3 +Bt describes the motion of a particular object,

with y having the dimension of length and t having the dimension of time. Determine the dimensions of the constants A and B. (Use the following as necessary:

L and T, where L is the unit of length and T is the unit of time.)

could be the possible concluding part of this question

let us give equate  the right hand side with dimension L

y=At^3 +Bt

y=(At^3)

y=has the dimension of length and t has the dimension of time, recall

L=AT^3

A=L/T^3

for B

L=BT

B=L/T

rick has $1400 and sally has $1500

step-by-step explanation:

to find amount of money rick has after 10 years :

principal = $1000 , time = 10 years , rate = 4% annually

to find amount of money sally has after 10 years :

her friend gives to pay her $50 per year, therefore money she has after 10 years = 50 × 10 = $500

also, sally gets $1000 after 10 years,

therefore, total amount of money sally has after 10 years = 500 + 1000 = $1500

so, after 10 years : rick has $1400 and sally has $1500

the football players are volunteering for the test.

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