There are 10 colored balls in a box ( 5 red, 3 blue, 2 green ). What is the probability of picking out a red ball and then a blue ball ( If I do not replace the red ball )?

At the beginning you have 10 balls, 5 of which are red. So, the chance of picking a red ball with the first pick is

When it comes to the second pick, you have 9 balls (because you didn't replace the first red ball), 3 of which are blue. So, you pick a blue ball with the second pick with probability

The two events will occur one after the other with the product of the probabilities:

false

step-by-step explanation:

rulers and compasses arent required in order to bisect an angle because when bisecting angles, you're making a "half circle" and considering in order to bisect an angle it wouldn't be straight, you wouldn't need either of the two

table a is wierd

step-by-step explanation:

6*f