A coffee shop sells lattes for $4 and cappuccinos for $3. Last Friday, the sales totaled $252. If the number of lattes sold was 6 more than 4 times the number of cappuccinos, how many lattes were sold?

Explanation:

This is a typical problem to solve with a system of two linear equations.

1. Name the variables:

2. First equation:

First equation: 4L + 3C = 252

3. Second equation:

Second equation: L = 6 + 4C

4. Solve the system:

Substitute L on the first equation with 6 + 4C

Solve:

Subsitute C = 12 in L = 6 + 4C

54 lattes were sold

40% off the regular price is the correct answer.

step-by-step explanation:

3

step-by-step explanation:

in standard form:

a= dictionaries

b= maps

you have to buy 3 dictionaries, so put a 3 next to the a (dictionaries) so that you can multiply them by each other.

a3+b= 60 (the amount of money you have)

we already know the cost of a=15 so replace a with $15

($15 x 3)+b=60

multiply 15 and 3 to get $45 and replace it with $45

45+b=60

and then replace b with 15 to get the total:

45+15=60

that means you have $15 left after buying 3 dictionaries.

15 divided by the cost of a map ($5) equals 3.

so you can buy 3 maps.

sorry if it was confusing!