Please hurry, this is also overdue and it's my last question. 15 points

(a) What is the equation of the line, written in slope-intercept form? Show how you determined the equation.

(b) Based on the linear model, predict how far Josh is away from home when he starts?. Approximately how fast is he traveling on his trip?

Step-by-step explanation:

a) The equation of a straight line, written in the slope-intercept form is expressed as

y = mx + c

Where c = intercept

Slope, m =change in value of y on the vertical axis / change in value of x on the horizontal axis

change in the value of y = y2 - y1

Change in value of x = x2 -x1

y2 = final value of y

y 1 = initial value of y

x2 = final value of x

x1 = initial value of x

From the graph,

y2 = 80

y1 = 120

x2 = 2

x1 = 1

Slope = (80 - 120)/(2 - 1) = - 40/1

= - 40 miles per hour

To determine the intercept, we would substitute x = 2, y = 80 and m= - 40 into y = mx + c. It becomes

80 = - 40 × 2 + c = - 80 + c

c = 80 + 80 = 160

The equation becomes

y = - 40x + 160

Where

x represents number of time.

y represents distance covered in miles

b) when she starts, x = 0

Therefore,

y = - 40 × 0 + 160

y = 160 miles

She was 160 miles from home when she started and her speed is

- 40 miles per hour

see explanation

step-by-step explanation:

a

(6r + 7) + (13 + 7r) ( remove brackets and collect like terms )

= 6r + 7 + 13 + 7r

= 13r + 20

b

remove brackets and collect like terms

13 - r - 1 + r

= 12 - r

c

remove brackets and collect like terms

= - 8 - r + 2r - 4

= - 12 + r

d

remove brackets and collect like terms

= 7r - - - 6r

[-   - = - - = - ]

= r -