A skateboard halfpipe is being designed for a competition. The halfpipe will be in the shape of a parabola and will be positioned above the ground such that its focus is 30 ft above the ground. Using the ground as the x-axis, where should the base of the halfpipe be positioned? Which equation best describes the equation of the halfpipe? (0, 60); y equals one over two hundred forty times x squared minus 60 (0, 60); y equals one over two hundred forty times x squared plus 60 (0, 15); y equals one over sixty times x square minus 15 (0, 15); y equals one over sixty times x squared plus 15

  0, 15); y equals one over sixty times x squared plus 15

Step-by-step explanation:

Assuming the halfpipe is only useful if the curve opens upward, the "base" (vertex) must be below the focus, so cannot be at (0, 60).

Apparently, the ground is supposed to be the directrix of the curve. Then the vertex is halfway between the focus and the ground, so is at (0, 15). The focus-vertex distance (p) is then 30-15 = 15, so the coefficient of the squared term is 1/(4p) = 1/(4·15) = 1/60.

For a vertex of (0, 15) and a vertical scale factor of 1/60, the equation of the curve is ...

  y = (1/60)x^2 +15 . . . . matches the last choice

include a picture of the drawing in order for me to

step-by-step explanation: