Triangle K M L is shown. Line L K extends through point J to form exterior angle J K M.
Which statement regarding the diagram is true?

m∠MKL + m∠MLK = m∠JKM
m∠KML + m∠MLK = m∠JKM
m∠MKL + m∠MLK = 180°
m∠JKM + m∠MLK = 180°

m∠KML + m∠MLK = m∠JKM

Step-by-step explanation:

we know that

An exterior angle of a triangle is equal to the sum of the opposite interior angles

so

In this problem

m∠JKM ----> is an exterior angle

m∠KML and m∠MLK are the opposite interior angles to m∠JKM

see the attached figure

therefore

m∠KML + m∠MLK = m∠JKM

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.

-2x + 7 = 7

subtract 7 from both sides.

-2x = 0

divide both sides by -2.

x = 0