A farmer has 2400 feet of fencing and wants to fence off a rectangular field that borders a straight river. Find the dimensions of the fence to maximize the area enclosed by the fence.

w- 600ft, L-1200ft

Step-by-step explanation:

Area = width*length

A(x) = x(2400-2x)

A(x) = 2400x - 2x^2

You have a quadratic with a = -2 and b = 2400

Maximum Area occurs where x = -b/2a = -2400/(2*-2) = 600 ft. (width)

length = 2400-2x = 2400-2*600 = 1200 (length)

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)