Roll two dice, one white and one red. Consider these events: A : The sum is 7 B : The white die is odd C : The red die has a larger number showing than the white D : The dice match (doubles) Which pair(s) of events are disjoint (events A and B are disjoint if A ∩ B = ∅ )? Which pair(s) are independent? Which pair(s) are neither disjoint nor independent?

Step-by-step explanation:

Roll two dice, one white and one red

A = The sum of 7 = [ (3,4),(4,3),(2,5),(5,2),(6,1),(1,6)]

B = the white die is odd = [(1,1),(1,3),(1,5),(2,1),(2,3),(2,5),(6,1),(6,3),(6,5),(3,1),(3,3),(3,5),(4,1),(4,3),(4,5),(5,1),(5,3),(5,5)]

C = Red die has larger number ; [(1,1),(2,2),(3,3),(4,4),(5,5),(6,6)]

a) AnC = ∅  disjoint

b) P(A) = 1/6, P(B) =1/2, P(C) = 1/6

P(AnB) = 1/12, P(AnC) =1/36, P(BnC) = 1/12

A and B, B and C are independent

-232

step-by-step explanation:

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v