A teacher decided to bring a jar of 530 pieces of small candy to his 100-student classroom so students could practice estimation. The students were told that whoever had the closest guess would win the candy. Suppose we took a random sample of one third of the students and calculated the sample mean of their guesses. The distribution of individual guesses had a mean of 400 pieces of candy and a standard deviation of 3,000 pieces of candy (the students had a lot of trouble guessing the count).

Yes, because the population distribution is normally distributed, and we have a random sample.

Step-by-step explanation:

If the population is skewed, then the sample mean won't be normal for when N is small.

If the population is normal, then the distribution of sample mean looks normal even if N = 2.

If the population is skewed, then the distribution of sample mean looks more and more normal when N gets larger.

Since we have use 33% of the student, then N is large enough to conclude that the student are bad at guessing

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation:

27 + 13x + 15 = (x + 5)( =

step-by-step explanation:

27 + 13x + 15 = (x + 5)( = 27 + 13x + 15 = (x + 5)( = 27 + 13x + 15 = (x + 5)( =