What is the equation of a line that passes through the point (-3, 1) and is parallel to a line with a slope of 2?

A.

y = 2x + 1

B.

y = 2x + 4

C.

y = 2x + 5

D.

y = 2x + 7

Slope-intercept form:  y = mx + b

[m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis]

For lines to be parallel, their slopes have to be the same.

Since you know:

m = 2       Then the parallel line's slope is also 2, so plug it into the equation

y = mx + b

y = 2x + b     To find b, plug in the point (-3, 1) into the equation

1 = 2(-3) + b

1 = -6 + b    Add 6 on both sides to get "b" by itself

1 + 6 = -6 + 6 + b

7 = b

y = 2x + 7          Your answer is D

answer: 0,6

step-by-step explanation:

this would make it the y intercept.

a. 12.5 kg

step-by-step explanation:

f = ma

so

m = f/a = (2500 n)/(200 m/s²) = 12.5 kg

1 n = 1 kg·m/s²