What is the equation of a line that passes through the point (-3, 1) and is parallel to a line with a slope of 2?

A.

y = 2x + 1

B.

y = 2x + 4

C.

y = 2x + 5

D.

y = 2x + 7

Slope-intercept form:  y = mx + b

[m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis]

For lines to be parallel, their slopes have to be the same.

Since you know:

m = 2       Then the parallel line's slope is also 2, so plug it into the equation

y = mx + b

y = 2x + b     To find b, plug in the point (-3, 1) into the equation

1 = 2(-3) + b

1 = -6 + b    Add 6 on both sides to get "b" by itself

1 + 6 = -6 + 6 + b

7 = b

y = 2x + 7          Your answer is D

i think it is everything has to equal 180 so, if i correct 4=c. 6=d. 8=a. 7=b. and the last question would be c. because they are parallel lines and they are congruent.

step-by-step explanation:

the reason everything has to equal to 180 is because that is how it works. i'm guessing that is its rule. 4 and 8 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 6 and 7 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 60+60 is 180. so, now you have your answer

a. 32 degrees

step-by-step explanation:

here we have to use the rule.

m∠e = 1/2 (major arc - minor arc)

m∠e = 1/2 (212 - 148)

m∠e = 1/2 (64)

m∠e = 32 degrees

answer: a. 32 degrees

you