A sample of weights of defensive tackles on Big 10 football teams are: Johnson, 202 pounds; Patrick, 215 pounds; Junior, 207 pounds; Kendron, 212 pounds; Nicko, 214 pounds; and Cochran, 208 pounds. What is the sample standard deviation (in pounds)?

the sample standard deviation is 4.926 pounds

Step-by-step explanation:

the sample standard deviation s is defined as

s =√[ 1/(n-1) ∑ ( x- m)²]  for x=1 to x=n

where

n= sample size = 10

x= weights of defensive tackles

m= sample mean

m= 1/n ∑ x*  for x=1 to x=n

then

m= 1/10 (202 + 215... +208) = 209.66 pounds

thus

s =√[ 1/(10-1) ∑ ( x- m)²] = √[ 1/(10-1) [ ( 202 - 209.66 )² + ( 215 - 209.66 )² +  ( 28 - 209.66 )² ] ] = 4.926 pounds

then the sample standard deviation is 4.926 pounds

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

a. she will receive a refund of $278.

step-by-step explanation: