The proportion of men in the population who have prostate cancer is 35 per 100,000. In 1980, a new test was developed to test for the presence of prostate cancer. The researchers who developed the test wanted to know the probability that a man who tested positive for prostate cancer actually had the disease. To find this probability, they took a SRS of 99 men known to have prostate cancer and a SRS of 150 men known not to have prostate cancer (after having a biopsy). Their test is a radioimmunoassay for prostate acid phosphatase (RIA-PAP). They found the following results (real data).3_28Let C = a randomly selected man has prostrate cancerUse 3 decimal places.(a) P(C | Pos) = (b) P(Cc | Pos) = (c) Can you use the table above to find P(C), the probability a randomly chosen male selected from the entire male population has prostate cancer?i. Yes, because it was an experiment. ii. No, because it was an observational study. iii. Yes, because the sample was taken randomly. iv. No, because the percentage of patients in the study with cancer is not representative of the percentage of people in the population with cancer.

d

step-by-step explanation:

by observation, we can see that the the graph is simply the graph of y = |x| that has been shifted 4 units downwards and 3 units to the left.

we can recognize in choice d :

y = | x + 3 |   - 4 (rewriting in general form)

y = | x - (- 3) |   - 4

the "-4 " term means   that the graph has been shifted by 4 units in the negative y direction

the "-3 " term means   that the graph has been shifted by 3 units in the negative x direction

this matches our observation of the graph described above.

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below:

step-by-step explanation:

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