Mathematics, 13.02.2020 22:46 tdun7003
Buses arrive at a specified stop at 15-minute intervals starting at 7A. M. That is, they arrive at 7, 7:15 ,7:30 ,7:45,and so on.
a) If a passenger arrives at the stopat a time that is uniformly distributed between 7 and 7:30, find the probability that he waits(a) less than 5 minutes for a bus;(b) more than 10 minutes for a bus
Answers: 3
![P=\int\limits^{15}_{10} {\frac{1}{30}} \, dx + \int\limits^{30}_{25} {\frac{1}{30}} \, dx\\\\ P=\frac{1}{30} [x]^{15}_{10}+\frac{1}{30} [x]^{30}_{25}\\\\P=\frac{1}{30}(15-10)+\frac{1}{30}(30-25)\\\\P=\frac{1}{3}](/tpl/images/0510/5790/d6f11.png)
![P=\int\limits^{5}_{0} {\frac{1}{30}} \, dx + \int\limits^{20}_{15} {\frac{1}{30}} \, dx\\\\ P=\frac{1}{30} [x]^{5}_{0}+\frac{1}{30} [x]^{20}_{15}\\\\P=\frac{1}{30}(5-0)+\frac{1}{30}(20-15)\\\\P=\frac{1}{3}](/tpl/images/0510/5790/9985b.png)
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Buses arrive at a specified stop at 15-minute intervals starting at 7A. M. That is, they arrive at 7...
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