The Pi Mu Epsilon mathematics honorary society of Outstanding Universitywishes to have a picture taken of its six officers. There will be two rowsof three people. How many different way can the six officers be arranged?

720

Step-by-step explanation:

I will use the following counting principle:

Product rule: if there are n ways of doing something, and m ways of doing another thing, there are n×m ways of doing both things.

First, we have to choose the 3 people that will be in the first row. This is a 3-element subset of  the set of six people, therefore there are ways of doing this.

Now, we have to arrange the order of the 2 lrows. Each one has 3 people, so there are 3!=6 ways to form one rows. Hence, there are 3!²=36 ways of arranging the two rows.

By the product rule, there are 20×36=720 ways of arrange the officers.

no, the equation would be invalid since they are both not equal.

step-by-step explanation:

here you got

4y-6+4y 2-9

first, you would simplify the equation on the form.

4y-6+4y 2-9

then, move all the terms that contains a y to the left and all the other terms to the right.

+4y-4y+-9-6

finally, you will simplify the left and the right side of the equation.

y=-3