A family has two children. If the genders of these children are listed in the order they are born, there are four possible outcomes: BB, BG, GB, and GG. Assume these outcomes are equally likely.
Let X represent the number of children that are girls.
Find the probability distribution of X.

P(X=0) = 0.25

P(X=1) = 0.50

P(X=2) = 0.25

Step-by-step explanation:

The possible outcomes of this event are: BB, BG, GB and GG.

There is one out of four events (GG) in which there are two girls (X=2).

There is one out of four events (BB) in which there are no girls(X=0).

There are two out of four events (GB and BG)) in which there is one girl (X=1).

Therefore, the probability distribution of X is:

P(X=0) = 1/4 = 0.25

P(X=1) = 2/4 = 0.50

P(X=2) = 1/4 = 0.25

step-by-step explanation:

a rhombus is a parallelogram enjoying his symmetry.

answer: -2+√x,-2-√x

i hope this , i don't know if you're looking for a pair or not.