You survey 127 employees, and learn that the number one thing on their wish list is free coffee. If 100 employees drink on average 1.5 cups of coffee a day and the cost is $.40 per cup, how much will it cost the company to offer free coffee for the year if the company is open 5 days a week all year?

If the company offers free coffee for the entire year, it will cost them $15,600.

Step-by-step explanation:

We're asked how much it would cost if 100 employees drink on average 1.5 cups of coffee a day for 5 days a week all year, with the knowledge that one cup of coffee costs 40 cents.

First, we have to find out how much it would cost for one employee. To do this, you can just multiply 1.5 by 0.40.

1.5 x 0.40 = 0.6, which means that the cost for one employee a day is $0.60

We know that there is going to be 100 employees that drink coffee, to find out how much it would cost for 100 employees a day, we multiply 0.60 by 100.

When multiplying decimals by 10s, you move the decimal point to the right based on how many zeroes there are when you're multiplying.

0.60 x 100 = 60

This means the company has to pay 60 dollars a day if there are 100 employees drinking 1.5 cups on average.

Now, the company is open 5 days a week all year. To find out how many days that is, we multiply how many weeks there are in a year by 5.

52 x 5 = 260

To finally solve the question, we multiply the amount it costs for 100 employees to drink 1.5 cups of coffee by the number of days the company is open:

260 x 60 = $15,600

It will cost the company $15,600 to offer free coffee for the year.

answer: your correct answer is b. d.

step-by-step explanation:

delaney would like to make a 5lb nut mixture that is 60% peanuts and 40% almonds.

she has several pounds of peanuts and several pounds of a mixture that is 20% peanuts and 80% almonds.

let 'p' represent the number of pounds of peanuts needed to make the new mixture, and  

let 'm' represent the number of pounds of the 80% almond-20% peanut mixture.

:

p + m = 5

therefore

m = (5-p)

write an equation based on the percent of peanuts

1p + .2m = .6(5)

replace m with (5-p)

p + .2(5-p) = .6(5)

p + 1 - .2p = 3

p - .2p = 3 - 1

.8p = 2

p = 2/.8

p = 2.5 lbs of peanuts required

then

5 - 2.5 = 2.5 lbs of the peanut/almond mixture required

:

a) what is the system that models this situation?

p + m = 5

1p + .2m = .6(5)