A standing wave pattern is observed in a thin wire with a length of3.00m. The equation of the wave is
y=(0.002m)sin(πx)cos(100πt)
where x is in meters and t is in seconds.

a. How many loops does this pattern exhibit?
b. What is the fundamental frequency of vibration of the wire?
c. If the original frequency is held constant and the tension inthe wire is increased by a factor of nine, how many loops arepresent in the new pattern?

a) How many loops does this pattern exhibit = 3Loops

b) What is the fundamental frequency of vibration of the wire = 50Hz

c) how many loops arepresent in the new pattern = 1 Loop

Step-by-step explanation:

The concept of general wave equation is applied and then compared to the equation given in the question to determine the amplitude A, and angular frequency w as shown in the attached file.

answer: answer

step-by-step explanation:

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.