The position function of a ball thrown into the air with a velocity of 23 ft/sec and initial height of 1 foot is given by the function s(t)= 16t2 +23t +1 where s(t) is the height of the ball above the ground after t seconds. Find the average velocity of the ball on the interval starting with 4 to the time 0.5 seconds later.

Step-by-step explanation:

The average velocity of an object is calculated as  the change in the distance over change in the time specified i.e

Hence we calculate the height at 4secs and at 4.5secs

at 4secs,

we also calculate the height at 4.5secs

Hence the average distance is

im pretty sure it would be 5 am, hope that , and give brainliest and guys if this is right then press the button and give 5 stars