During the past six months, 73.2 percent of US households purchased sugar. Assume that these expenditures are approximately normally distributed with a mean of $8.22 and a standard deviation of $1.10. What proportion of the households spent between $5.00 and $9.00 on sugar

75.94% of the households spent between $5.00 and $9.00 on sugar.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean and standard deviation , the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

What proportion of the households spent between $5.00 and $9.00 on sugar?

This is the pvalue of Z when X = 9 subtracted by the pvalue of Z when X = 5. So

X = 9

has a pvalue of 0.7611

X = 5

has a pvalue of 0.0017.

So 0.7611 - 0.0017 = 0.7594 = 75.94% of the households spent between $5.00 and $9.00 on sugar.

answer: the center is the median and/or mean of the data. the spread is the range of the data. and, the shape describes the type of graph. the four ways to describe shape are whether it is symmetric, how many peaks it has, if it is skewed to the left or right, and whether it is uniform. good luck

step-by-step explanation: