Pls help

The rectangle shown has a perimeter of 136 cm and the given area. Its length is 8 more than five times its width. Write and solve a system of equations to find the dimensions of the rectangle.

Length = 58, width = 10

Step-by-step explanation:

Given:

Perimeter = 136 cm

Length = 5 * width + 8

Find dimensions of rectangle

Solution:

Write two equations

L = length, W = width

2(L+W) = 136 (1)

L = 5W+8 (2)

substitute (2) in (1)

2(5W+8 + W) = 136

6W+8 = 136/2 = 68

6W = 68-8 = 60

W = 60/6 = 10

L = 5W+8 = 5(10)+8 = 58

none.

step-by-step explanation:

m

1

=

5

m1=5

b

=

−

1

b=-1

find the slope and y-intercept of the second equation.

tap for more

m

2

=

0

m2=0

b

=

−

6

b=-6

compare the slopes

m

m of the two equations.

m

1

=

5

,

m

2

=

0

m1=5,m2=0

compare the two slopes in the decimal form. if the slopes are equal, then the lines are parallel. if the slopes are not equal, then the lines are not parallel.

m

1

=

5

,

m

2

=

0

m1=5,m2=0