Rewrite the expression in the form a^n a^5xa^-3

Work Shown:

I'm assuming the "x" means "multiply", and it is not a variable.

a^5 * a^(-3) = a^(5+(-3)) = a^(5-3) = a^2

The rule I'm using is

a^b*a^c = a^(b+c)

The base is always the same. We add the exponents.

The expression a^2 is in the form a^n with n = 2.

hello :

by applying the distributive property :

6 × 4.3 = 6 × ( 4 + 0.3 )

            =   (6 ×   4) + (6 ×   0.3)

            = 24 + 1.8

6 × 4.3 = 25.8