A Ferrari is heading south at a constant speed on Broadway (a north/south street) at the same time a Mercedes is heading west on Aloha Avenue (an east/west street). The Ferrari is 624 feet north of the intersection of Broadway and Aloha, at the same time that the Mercedes is 400 feet east of the intersection. Assume the Mercedes is traveling at the constant speed of 32 miles/hour.

Find the speed of the Ferrari so that a collision occurs in the intersection of Broadway and Aloha.

49.92 miles/hour

Step-by-step explanation:

32 miles/hour = 32 * 5280 = 168960 ft/hour

For the collision to occur, both cars must arrive at the intersection at the same time.

The time it takes for the Mercedes to travel 400 feet at the rate of 168960 ft/hour is 400 / 168960 = 0.002367 hours

So the Ferrari should take the same time to travel 624 feet as well, its speed would be

624 / 0.002367 = 263577.6 ft/hour or 263577.6 / 5280 = 49.92 miles/hour  

10 cm

step-by-step explanation:

if the polygon is a rectangle, then the perimeter is x+x+y+y. using the values that you gave, the perimeter is 3+3+2+2=10cm.

step-by-step explanation:

the original amount doesn't ''re just looking for the time it takes for 1/2 of the substance to we have

(1/2) =)     take the ln   of both sides

ln (1/2)   = )   and we can write

ln(1/2) = ) lne     and lne   = 1     so we have

ln(1/2) = -.1092t     divide both sides by -.1092

t = ln(1/2)/-.1092 = about 6.347 days = about 6.3 days (rounded)