Solve this equation for b. (3+2)-b=1

b = 4

Step-by-step explanation:

First, 3 + 2 = 5

This can be substituted to 5 - b = 1

Subtract 5 from both sides leaving -b = -4

We don't want be to be negative so we divide the imaginary -1 that's in front of the b from both sides

This leaves b = 4

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.

the answer is 11.2 (i know i’m late)