A surveyor standing at point A sights two targets, one at B and one at C. He measures that target [5 pts] B is 87 yards away, target C is 459 yards away and the angle between them is 41 degrees. Use solve and the Law of Cosines to find the distance between B and C. Assign to p10. Note: Using solve applied directly to the LOC will yield both a positive and negative solution - please do this. And how to code in mathlab

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.

alright well the answers to your question is

2xy/9 hope this have a nice day : )

step-by-step explanation: