Mathematics, 11.02.2020 20:25 hardwick744
Solve the equation in the interval from \dfrac{3\pi}{2} 2 3π start fraction, 3, pi, divided by, 2, end fraction too \dfrac{9\pi}{2} 2 9π start fraction, 9, pi, divided by, 2, end fraction. Your answer should be in radians. All choices are rounded to the nearest hundredth. \sin(x)=0.65sin(x)=0.65.
Answers: 2
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. We are asked to solve the given equation in the interval ![[\frac{3\pi}{2},\frac{9\pi}{2}]](/tpl/images/0506/9922/7dd06.png)
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:
is greater than 
, therefore, the solutions for the given equation are 
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Solve the equation in the interval from \dfrac{3\pi}{2} 2 3π start fraction, 3, pi, divided by, 2,...
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