Find the solution for this system of equations.
2x + 4y = 8
x = 3y - 6

x = 0 , y = 2

Step-by-step explanation:

Solve the following system:

{2 x + 4 y = 8 | (equation 1)

x = 3 y - 6 | (equation 2)

Express the system in standard form:

{2 x + 4 y = 8 | (equation 1)

x - 3 y = -6 | (equation 2)

Subtract 1/2 × (equation 1) from equation 2:

{2 x + 4 y = 8 | (equation 1)

0 x - 5 y = -10 | (equation 2)

Divide equation 1 by 2:

{x + 2 y = 4 | (equation 1)

0 x - 5 y = -10 | (equation 2)

Divide equation 2 by -5:

{x + 2 y = 4 | (equation 1)

0 x+y = 2 | (equation 2)

Subtract 2 × (equation 2) from equation 1:

{x+0 y = 0 | (equation 1)

0 x+y = 2 | (equation 2)

Collect results:

{x = 0 , y = 2

395.84

step-by-step explanation:

2πrh+2πr²

2 (pie)(radius)(height)+2(pie)(radius)^2

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation: