GIVING 30 POINTS FOR THIS AND WILL AWARD BRAINLIEST!!!
Yesterday I posted this one and no one answered and I need it badly so please help...

Explain the difference between using the cosine ratio to solve for a missing angle in a right triangle versus using the secant ratio. You must use complete sentences and any evidence needed (such as an example) to prove your point of view.

Answer with Explanation:

The basic trigonometric ratios are sine, cosine and tangent.

When you are using the cosine ratio, you find the missing angle in a right triangle by using this formula:

cos = , the adjacent side of the right triangle is the side next to it, while the hypotenuse is the "opposite side" of the angle. The hypotenuse is considered the longest side.

The reciprocal trig. ratio of cosine is secant. When using the secant ratio, you find the missing angle in a right triangle by using this formula:

sec = , as you can see, the cosine formula was just inverted for the secant formula.

Remember to follow the "pythagorean theorem" when using the formulas.

For example, if you want to find cos A in △ABC (I have attached an image of the problem to be solved), then you have to follow these steps:

1. cos (A) =

2. cos (A) =

3. cos (A) = (this is the answer)

The basic trigonometric ratios are sine, cosine and tangent.

the reciprocal trig. ratio of sine (sin) is cosecant (csc)

the reciprocal trig. ratio of cosine (cos) is secant (sec)

the reciprocal trig. ratio of tangent (tan) is cotangent (cot)

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Step-by-step explanation:

a)(x-2)^2+(y-1)^2=9

step-by-step explanation:

(picture explains)