1. The ages (in years) and weights (in pounds) of all wide receivers for a football team are listed. Find the coefficient of variation for each of the two data sets. Then compare the results. Weights:214 185 201 213 211 197 188 220Ages:25 28 23 26 29 26 26 27
2. Compare the results. What can you conclude?A. Ages are more variable than weights for all wide receivers on this team. B. Weights are more variable than ages for all wide receivers on this team. C. Ages and weights for all wide receivers on this team have about the same amount of variability.

1)

Weights: =0.06321578

Ages: =0.06980003

2)  A) Ages are more variable than weights for all wide receivers on this team

Step-by-step explanation:

The coefficient of variation is calculated as follows

where s is the sample standard deviation and x bar is the sample mean,

where

∑(xi-x bar)^2/(n-1)

xi=i observation, n is the sample size

and,  x bar = ∑(xi) / n

amount of oatypop that contains the prize = 40%

amount   of oatypop which doesn't contain the prize = (100-40)=60%

probability that hannah will win a prize

    = s +f s +f f s+ff   f s+ff f f s+ infinity.where f= failure,s= success

=   or 60%

probability that hannah only has to buy 3 or less boxes before getting a prize= (s) and ( f s) and (ff s) and (f f f s)

        = = 87.04 %  

step-by-step explanation:

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x