Matt and Seth purchase baseball cards each week. the amount of cards they each have in their collection is shown in the graph and table. who will have more cards in week 20?

In week 20, Seth will have 80 cards and Matt will have 60.

Step-by-step explanation:

Let's find out the amount of cards that Math and Seth will have in week 20, using the information shown in the graph and table:

Amount of cards Seth has in week 20 = 20 * 4 = 80

The equation to find out the amount of cards, c, Seth has in week w:

c = 4w

Amount of cards Matt has in week 20 = 20 + (2 * 20) = 20 + 40 = 60

The equation to find out the amount of cards, c, Matt has in week w:

c = 20 + 2w

In week 20, Seth will have 80 cards and Matt will have 60.

Note: Same solution to question 14725490, answered by me today.

answer: 20

step-by-step explanation: subtract the minimum date value from the maximum data value to find the date range. in this casem the date range is 42 - 22 = 20

hope this ! : ) ~zane

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2