Kathi and Robert Hawn had a pottery stand at the annual Skippack Craft Fair. They sold some of their pottery at the original price of $ 13.50 each, but later decreased the price of each by $3.00. If they sold all 91 pieces and took in $ 1 comma 030.50, find how many they sold at the original price and how many they sold at the reduced price.

they sold 25 at the original price they sold 66 at the reduced price.

Step-by-step explanation:

Let x represent the number of pottery that they sold at the original price.

Let y represent the number of pottery that they sold at the reduced price.

They sold a total of 91 pieces of pottery. This means that

x + y = 91

They sold some of their pottery at the original price of $ 13.50 each, but later decreased the price of each by $3.00. The reduced price would be 13.5 - 3 = $10.5

If they made $1030.5 in total, it means that

13.5x + 10.5y = 1030.5 - - - - - - - - - 1

Substituting x = 91 - y into equation 1, it becomes

13.5(91 - y)+ 10.5y = 1030.5

1228.5 - 13.5y + 10.5y = 1030.5

- 13.5y + 10.5y = 1030.5 - 1228.5

- 3y = - 198

y = - 198/ - 3

y = 66

x = 91 - y = 91 - 66

x = 25

option 3 . (5x + 1) - (-10x + 6)

step-by-step explanation:

option 1 :

(4x + 3) + (-9x + 4)

or 4x+3 -9x + 4

or -5x + 7

option 2

(x - 2) - (6x - 9)

or x-2-6x + 9

or -5x + 7

option 3

(5x+ + 6)

or 5x + 1 + 10x -6

or 15x -5

option 4

-4x+2x+7-3x

-7x + 2x + 7

-5x + 7

hence only option 3 did   not satisfy the given simplify expression.