Rickey has been commissioned to paint a mutual that is allowed to have an area 60 square meters to make the rectangulr shape of the mural pleasing the eye Rickey wants the length to be 15 meters longer than twice its width ehat length should Rickey use for the mural

Length of the mural should be 20.78 m

Step-by-step explanation:

Let the length of the mural be L and the width W

Area = L × W = 60 m²

Ticket wants the L = 15 + 2W

Substitute for L in the Area eqn

(15 + 2W) × W = 60

15W + 2W² = 60

2W² + 15W - 60 = 0

Solving the quadratic equation

W = 2.89 m or - 10.39 m

Obviously, the width cannot be negative,

So, W = 2.89 m

L = 15 + 2W = 15 + 2(2.89) = 20.78 m

Check - L × W = 20.78 × 2.89 = 60 m²

Hope this Helps!!!

18.8cm hope i at all

step-by-step explanation: