Show that when x 0 not equals 0x0≠0, the differential equation can't possibly have a solution in a neighborhood of xequals=x 0x0 that satisfies y (x 0 )equals 0yx0=0. Substituting the initial condition into the differential equation gives 25 (nothing )StartFraction dy Over dx EndFraction minus 36 (nothing )equals 025 dy dx−36=0. This equation can be simplified to StartFraction dy Over dx EndFraction equals 0 comma dy dx = 0, which is equivalent to the given condition that y (x 0 )equals 0.