If h(x) = 5 for the function h(x) = 2x + 1, what is the value of x?
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x = 2 .

Step-by-step explanation:

Given  : If h(x) = 5 for the function h(x) = 2x + 1, .

To find : what is the value of x?  

Solution : We have given

h(x) = 5 for the function h(x) = 2x + 1,

Now plug the h(x) = 5.

2x + 1 = 5 .

On subtracting both sides by 1

2x  = 5 -1 .

2x = 4

On dividing both sides by 2 .

x = 2 .

Therefore, x = 2 .

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation:

to plot points   for x just start at the origin (middle) and go to the left however many times it say(if the number is a positive) if the number is a negative then go right however many times it says if it is 0 go nowhere

now keep you pencil there and go up however many times it says on y(if it is positive) if it is negative then go down however many times it says. if it says 0 go nowhere.

you have just plotted a point! now when you finish plotting all of them connect them with a ruler

plot each point as (-3, 7), (0,4), (3,1), (8,-4)   in the parenthesis on the left of the comma is x and the right is y.