A block of mass 15 kg is sliding along the ice at constant speed 4.0 m/s. just ahead of it is a block of mass 23 kg sliding in the same direction at constant speed 3.6 m/s. when the two blocks collide, the 23-kg block travels at a new speed of 5.2 m/s. what is the new speed of the 15-kg block?

nope lol

step-by-step explanation:

7.9m and 4.3°

step-by-step explanation:

let east be +x and north be +y, x = distance * cos θ, y = distance * sin θ  

for 3.5 south, y = -3.5  

for 8.2, x = 8.2 * cos 30 and y = 8.2 * sin 30  

for 15 west, x = -15  

total x = 8.2 * cos 30 – 15 ≈ -7.9  

total y = -3.5 + 8.2 * sin 30 = 0.6  

magnitude = [(8.2 * cos 30 – 15)^2 + 0.6^2)]^0.5  

the magnitude is approximately 7.9 m  

tan θ = y/x = 0.6/-7.9  

the angle is approximately 4.3˚ north of west

8(1/6)

step-by-step explain:

49/6= 48

8 (1/6)