A stadium has 53,000. Seats sell for $ 42 in Section A, $ 36 in Section B, and $ 30 in Section C. The number of seats in Section A equals the total number of seats in Sections B and C. Suppose the stadium takes in $ 1,992,600 from each sold-out event. How many seats does each section hold

a28=58

step-by-step explanation:

a1=a1+(n-1)d

a28= 4+ (28-1)2

a28=4+(27)(2)

a28=4+54

a28=58

the answer is c: divide the arc's degree measure by 360°, then multiply by the circumference of the circle.

where is the picture

step-by-step explanation:

this is a direct variation proportion. y = kx

y is the total amount due, k is the constant of variation, and x is the number of texts sent.

plug in the 3.20 and the 16 to solve for the "k". this is the constant of proportionality. it is the value that will not change.

3.20 = k(16). solving you get $.20 per text.

the equation would then be y = .20x