Estimate the slope of the tangent line to each curve at the point (x, y).

I know the answers, I just don't know how to get to the answers

5. 2

7. 1/4

9. 0

7. On the x axis, from -2 to 2 is 4 units

On the y axis at -2 the tangent is at y 2, at x = 2 the line is at about y=3

The slope would be (3-2) / (2 - -2)

Slope = 1/4

9. The line is a straight line so there is no slope. Slope = 0

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)