If pirate Jack splits all of his coins into 7 equal parts for his parents he has for coins left or if he splits all of his coins into 11 equal piles for the Shipmates he has four coins left us jamming every every file has at least one coins what is the least possible number of coins pirate Jack has

Question:

Pirate Jack has an equal number of gold and silver coins. If Pirate Jack splits all of his coins into 7 equal piles for his parrots, he has 4 coins left. Or, if he splits all of his coins into 11 equal piles for his shipmates, he has 4 coins left. Assuming every pile has at least 1 coin, what is the least possible number of coins Pirate Jack has?

The least possible number of coins pirate Jack has is 77.

Step-by-step explanation:

Let the number of coins in the piles for the parrots be x.

So, the total number of coins be 7x + 4(1)

Let the number of coins in the piles for for the pirates be y.

Their total number of coins will be 11y + 4(2)

Both the number of coins are equal. So equating the equation (1) and (2)

7x + 4 =   11y + 4

7x = 11 y

Thus the least possible number of coins that Pirate Jack has is equal to the LCM of 11 and 7.

LCM of 11 = 11

LCM of 7 = 7

LCM of 11 and 7 = 77

because they could drop even lower..

560

hope this : )