Afootball is kicked vertically upward from a height of 3 feet with an initial speed of 70 feet per second. the formula h=3+70t-16t^2 describes the ball's height above the ground, h, in feet, t seconds after it was kicked. use this formula to find the ball's height 3 seconds after it was kicked.
q. the ball's height, 3 seconds after it was kicked, was
feet.

69 feet

Step-by-step explanation:

3 seconds is a unit of time, t.  So if we want the height of the ball, h, 3 seconds after it was kicked, we plug in 3 for t and solve for h:

which simplifies to

h = 3 + 210 - 144 so

h = 69 feet

based on context clues you gave i'm assuming the answer would be c.

answer: 140

step-by-step explanation:

so just add all then it will be your answer but i am not pretty sur eif it is but hope this i am here to people