Which shows one way to determine the factors of x3 + 5x2 – 6x – 30 by grouping?
x(x2 – 5) + 6(x2 – 5)
x(x2 + 5) – 6(x2 + 5)
x2(x – 5) + 6(x – 5)
x2(x + 5) – 6(x + 5)

One way to determine the factors of :

x³ + 5x² - 6x - 30 = x² ( x + 5 ) - 6 ( x + 5 )

If equation ax³ + bx² + cx + d = 0 has roots x₁ , x₂ , and x₃ then

Let us now tackle the problem!

To factor the equation given can be done in the following way

→ group it into two parts

→ factorize both parts

Grade: High School

Subject: Mathematics

Chapter: Polynomial

Keywords: Quadratic , Equation , Discriminant , Real , Number , Polynomial , Factors

144.50

step-by-step explanation:

21.5 x 13.4=288.10 divide by 2

∡ eia and ∡ kij are congruent

step-by-step explanation: